1/x^2-5x=x+7/x-1

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Solution for 1/x^2-5x=x+7/x-1 equation: 



1/x^2-5x=x+7/x-1

We move all terms to the left:

1/x^2-5x-(x+7/x-1)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x-1)!=0

x∈R



We add all the numbers together, and all the variables

-5x+1/x^2-(x+7/x-1)=0

We get rid of parentheses

-5x+1/x^2-x-7/x+1=0

We calculate fractions

We do not support expression: x^3

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